Question
$f(x)=x^x$ has a stationary point at

Answer

(b) : We have, $f(x)=x^x$
$\Rightarrow f^{\prime}(x)=x^x(1+\log x)$
For stationary point, $f^{\prime}(x)=0$
$
\Rightarrow x^x(1+\log x)=0 \Rightarrow x=\frac{1}{e}
$

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