MCQ
$Ge\,(II)$ compounds are powerful reducing agents whereas $Pb\,(IV)$ compounds are strong oxidants. It can be due to
  • A
    $Pb$ is more electropositive than $Ge$
  • B
    Ionization potential of lead is less than that of $Ge$
  • C
    Ionic radii of $Pb^{2+}$ and $Pb^{4+}$ are larger than those of $Ge^{2+}$ and $Ge^{4+}$
  • More pronounced inert pair effect in lead than in $Ge$

Answer

Correct option: D.
More pronounced inert pair effect in lead than in $Ge$
d
$Ge\,(II)$ tends to acquire $Ge\,(IV)$ state by loss of electrons. Hence it is reducing in nature. $Pb\,(IV)$ tends to acquire $Pb\,(II)$ $O.S$. by gain of electrons. Hence it is oxidising in nature. This is due to inert pair effect.

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