MCQ
General solution of $\tan 5 \theta=\cot 2 \theta$ is
- ✓$\theta=\frac{n \pi}{7}+\frac{\pi}{14}$
- B$\theta=\frac{ n \pi}{7}+\frac{\pi}{5}$
- C$\theta=\frac{ n \pi}{7}+\frac{\pi}{2}$
- D$\theta=\frac{ n \pi}{7}+\frac{\pi}{3}$
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