\(\therefore \,[CO_3^ - ] = 1.0 \times {10^{ - 4}}\,M\)
\(i.e.\,\,\,s = 1.0 \times {10^{ - 4}}\,M\)
At equilibrium
\([B{a^{ + + }}][CO_3^ - ] = {K_{sp}}\,of\,BaC{O_3}\)
\([B{a^{ + + }}] = \frac{{{K_{sp}}}}{{[CO_3^ - ]}} = \frac{{5.1 \times {{10}^{ - 9}}}}{{1.0 \times {{10}^{ - 4}}}}\)
\( = 5.1 \times {10^{ - 5}}\,M\)
${H_2}{O_2}\, + \,{H_2}O\, \rightleftharpoons \,{H_3}{O^ + }\, + \,HO_2^ - $