MCQ
Give the truth table for the circuit shown in figure 
  • $\begin{array}{*{20}{c}}
    A&B&X\\
    0&0&0\\
    0&1&1\\
    1&0&1\\
    1&1&0
    \end{array}$
  • B
    $\begin{array}{*{20}{c}}
    A&B&X\\
    0&0&1\\
    0&1&0\\
    1&0&0\\
    1&1&1
    \end{array}$
  • C
    $\begin{array}{*{20}{c}}
    A&B&X\\
    0&0&0\\
    0&1&0\\
    1&0&0\\
    1&1&1
    \end{array}$
  • D
    $\begin{array}{*{20}{c}}
    A&B&X\\
    0&0&1\\
    0&1&1\\
    1&0&1\\
    1&1&0
    \end{array}$

Answer

Correct option: A.
$\begin{array}{*{20}{c}}
A&B&X\\
0&0&0\\
0&1&1\\
1&0&1\\
1&1&0
\end{array}$
a
First we consider the output $C$ of the $NAND$ gate:

$\begin{array}{*{20}{c}}
A&B&C\\
0&0&1\\
0&1&1\\
1&0&1\\
1&1&0
\end{array}$

Next we consider the state $D$ which is the output of an $AND$ gate operating on $A$ and $C:$

$\begin{array}{*{20}{c}}
A&B&C&D\\
0&0&1&0\\
0&1&1&0\\
1&0&1&1\\
1&1&0&0
\end{array}$

Similarly, $E$ is the output of an $AND$ gate operating on $B$ and $C:$

$\begin{array}{*{20}{c}}
A&B&C&D&E\\
0&0&1&0&0\\
0&1&1&0&1\\
1&0&1&1&0\\
1&1&0&0&0
\end{array}$

Finally, the output $X$ is the result of an $OR$ gate operating on $D$ and $E:$

$\begin{array}{*{20}{c}}
A&B&C&D&E&X\\
0&0&1&0&0&0\\
0&1&1&0&1&1\\
1&0&1&1&0&1\\
1&1&0&0&0&0
\end{array}$

We recoginise this as the exclusive - or $(XOR)$ function.

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