Question
Given a line BC and a point A on it, construct a ray AD using set squares so that $\angle\text{DAC}$ is:
150°
150°
✓
Answer
Draw a line BC and take a point A on it. Place 30° set-square on the line BC such that its vertex of 30° angle lies on point A and one edge coincides with the ray AB as shown in the figure. Draw the ray AD.
Therefore, $\angle\text{DAB}=30^{\circ}$ We know that angle on one side of the straight line will always add to 180° Therefore, $\angle\text{DAB}+\angle{\text{DAC}}=180^{\circ}$ Therefore, $\angle\text{DAC}=150^{\circ}$
Therefore, $\angle\text{DAB}=30^{\circ}$ We know that angle on one side of the straight line will always add to 180° Therefore, $\angle\text{DAB}+\angle{\text{DAC}}=180^{\circ}$ Therefore, $\angle\text{DAC}=150^{\circ}$
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