Maths 3 Mark Question

Mark two points, A and B on a piece of paper and join them as follows:
To measure the length of AB, place the ruler with its edge along AB, such that the zero mark of the cm side of the ruler coincides with point A, as shown in the figure. Now, read the mark on the ruler, which corresponds to the point B. The reading on the ruler at point B is the length of the line segment AB. Here, AB = 5.6cm To draw the line segment that is half AB, we draw a line/ and take a point C on it. Now, using a ruler, we measure the line segment AB and here, AB = 5.6cm Half of AB = 5.62 = 2.8cm Now, we take a divider and open it so much that its end of one hand is at 0 and end of the another hand is at 2.8cm. Then, we lift the divider and place one end at C and the other end on the line l at point D.

Mark two points, A and B on a piece of paper and join them as follows:
To measure the length of AB, place the ruler with its edge along AB, such that the zero mark of the cm side of the ruler coincides with point A, as shown in the figure. Now, read the mark on the ruler, which corresponds to the point B. The reading on the ruler at point B is the length of the line segment AB. Here, AB = 5.6cm To draw the line segment twice AB, draw a line/ and take a point C on it. Now, take a divider and open it such that the end points of both its arms are at A and B. Then, lift the divider and without disturbing its opening, place one end-point at C and the other end-point on the line 1, as shown in the figure. Lift the divider and place one end-point at E and the other end-point on the line 1, opposite C. Name this point D.

Given: AB= 7.5cm and CD = 2.5cm Draw AB and CD
Draw a line l and take a point E on it. Now, take a divider and open it such that ends of both the arms are at A and B. Then, we lift the divider and place its one end at E and other end (F) and on the line l as shown in figure. Now, reset the divider in such a way that the end of its one hand is at C and the end of the other hand is at D. Then, we lift the divider and place its one end at E and other end (G) on the line l as shown in the figure. FG is required line segment, whose length is equal to (AB - CD)

Given: AB= 7.5cm and CD = 2.5cm Draw AB and CD
Draw a line l and take a point E on it. Now a take a divider and open it such that the ends of both its arms are at A and B. Then, we lift the divider and place its one end at E and other end (say F) on the line l as shown in the figure. Again, lift the divider and place its one end F and other end on the line l, opposite to E. Let this point be G. EG is required line segment, whose length is equal to 2AB.

Mark two points, A and B on a piece of paper and join them as follows:
To measure the length of AB, place the ruler with its edge along AB, such that the zero mark of the cm side of the ruler coincides with point A, as shown in the figure. Now, read the mark on the ruler, which corresponds to the point B. The reading on the ruler at point B is the length of the line segment AB. Here, AB = 5.6cm

Extend the line segment QP towards point zero of the ruler and take a point 0 on the extended line QP corresponding to point zero on the ruler.
From the figure, we can say:
OP = 4cm and OQ = 14.8cm
Now, PQ = OQ - OP
= (14.8 - 4)cm
= 10.8cm

A line can be drawn to infinity in both the directions. AB is a line.
A line segment has both ends fixed. EF is a line segment. A ray has one end fixed and another end can be drawn to infinity. CD is a ray.

Mark two points, A and B on a piece of paper and join them as follows:
To measure the length of AB, place the ruler with its edge along AB, such that the zero mark of the cm side of the ruler coincides with point A, as shown in the figure. Now, read the mark on the ruler, which corresponds to the point B. The reading on the ruler at point B is the length of the line segment AB. Here, AB = 5.6cm To draw the line segment three times A, we draw a line / and take a point C on it. Now take a divider and open it, such that the end-points of both its arms are at A and B. Then, we lift the divider and place one end-point at C and the other end-point on the line 1, as shown in the figure. Let this point be E. Again, lift the divider and place one end-pint at E and the other end-point on the line 1, opposite to C. Let this point be F. Again, lift the divider and place one end-point at F and the other end-point on the line 1, opposite to C. Name this point D.

Given: AB= 7.5cm and CD = 2.5cm Draw AB and CD
We draw a line l and take a point E on it. Now, take a divider and open it such that the ends of both its arms are A and B. The, we lift the divider end (F) on the line l, as shown in the figure. Now, reset the divider in such a way that the end of its one hand is at C and the end of the other hand is at D. Then, we lift the divider and place its one end at F and another end (G) on the line l opposite to E as shown in the figure. EG is required line segment, whose length is equal to (AB + CD)

Given: AB= 7.5cm and CD = 2.5cm Draw AB and CD
Draw a line l and take a point E on it. Now take a divider and open it such that the ends of both its arms are at C and D. Then, we lift the divider and place its end at E on it and other end (F) on the line l, as shown in the figure. Again, we lift the divider end (G) on the l opposite to C. Again, lift the divider end (G) on the line l opposite to C. Again, lift the divider and place its one end at G and another end (H) on the line l, opposite to E. EH is required line segment, whose length is equal to 3CD.