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Matrices — Mathematics STD 10 — Question

ICSE BoardEnglish MediumSTD 10MathematicsMatrices2 Marks
Question
Given $A=2\left[\begin{array}{ll}2 & 1 \\ 3 & 0\end{array}\right],-3\left[\begin{array}{ll}1 & 1 \\ 5 & 2\end{array}\right]+\left[\begin{array}{cc}-3 & -1 \\ 0 & 0\end{array}\right]$ Find $2A - 3B + C$
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Answer

$2A - 3B + C$
$\begin{array}{l}=2\left[\begin{array}{ll}2 & 1 \\ 3 & 0\end{array}\right]-3\left[\begin{array}{ll}1 & 1 \\ 5 & 2\end{array}\right]+\left[\begin{array}{cc}-3 & -1 \\ 0 & 0\end{array}\right] \end{array} $
$ =\left[\begin{array}{ll}4 & 2 \\ 6 & 0\end{array}\right]-\left[\begin{array}{cc}3 & 3 \\ 15 & 6\end{array}\right]+\left[\begin{array}{cc}-3 & -1 \\ 0 & 0\end{array}\right]  $
$=\left[\begin{array}{cc}4-3-3 & 2-3-1 \\ 6-15+0 & 0-6+0\end{array}\right]  $
$=\left[\begin{array}{l}-2-2 \\ -9-6\end{array}\right]$

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