Question
Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24th term of this progression.
✓
Answer
Given A.P. is 12, 16, 20, 24, . . .
Where first term a = 12
Second term t1 = 16
Third term t2 = 20
Common Difference d = t2 – t1 = 20 – 16 = 4
We know that, nth term of an A.P. is
tn = a + (n – 1)d
We need to find the 24th term,
Here n = 24
Thus, t24 = 12 + (24 – 1)× 4
t24 = 12 + (23)× 4 = 12 + 92 = 104
Thus, t24 = 104
Where first term a = 12
Second term t1 = 16
Third term t2 = 20
Common Difference d = t2 – t1 = 20 – 16 = 4
We know that, nth term of an A.P. is
tn = a + (n – 1)d
We need to find the 24th term,
Here n = 24
Thus, t24 = 12 + (24 – 1)× 4
t24 = 12 + (23)× 4 = 12 + 92 = 104
Thus, t24 = 104
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