Question
Given below is the frequency distribution table regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days.
Concentration of $SO_2$
0.00 - 0.04
0.04 - 0.08
0.08 - 0.12
0.12 - 0.16
0.16 - 0.20
0.20 - 0.24
No. of days
4
8
9
2
4
3
Find the probability of the concentration of sulphur dioxide in the interval 0.12 - 0.16 on any of these days.

Answer

Total no of days: 30 Probability of concentration of $SO_2$ in interval 0.12 - 0.16
$=\frac{\text{Favorable out come}}{\text{Total out come}}$
$=\frac{2}{30}$
$=\frac{1}{15}$
$=0.06$

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