MCQ
Given
$E^o_{Cl_2/Cl^-} = 1.36\,V,$ $E^o_{Cr^{3+}/Cr}= -0.74\,V,$
$E^o_{Cr_2/O_7^{2-}/Cr^{3+}}=1.33\,V,$ $E^o_{MnO^-_4/Mn^{2+}} = 1.51\,V$
Among the following, the strongest reducing agent is
- ✓$Cr$
- B$Mn^{2+}$
- C$Cr^{+3}$
- D$Cl^-$
✓
Answer
Correct option: A.
$Cr$
a
Lower the reduction potential, greater is the tendency of the element to get oxidized, hence, greater is the reducing ability. Since, chromium system has lowest reduction potential; therefore, it is the strongest reducing agent.
Lower the reduction potential, greater is the tendency of the element to get oxidized, hence, greater is the reducing ability. Since, chromium system has lowest reduction potential; therefore, it is the strongest reducing agent.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following compounds is most rapidly hydrolysed by $S_{N^{1}}$ mechanism.
→Product $(C)$ of the above reaction is
→The pair in which both the species have the same magnetic moment (spin only) is :
$C{r_2}O_7^{2 - } + {I^ - } \to {I_2} + C{r^{3 + }}$
→${E^0}_{cell} = 0.79\;V$
$E_{C{r_2}O_7^{2 - }}^0 = 1.33\;V,\;{E^0}_{{I_2}}$ is ........... $\mathrm{V}$
The major product obtained on interaction of phenol with sodium hydroxide and carbon dioxide is
The element having general electronic configuration $3{d^4}4{s^1}$ is
→The flame colours of metal ions are due to:
$Xe{F_4}$ Processing strongly with water gives .......
→Aqueous solution of $K _2 Cr _2 O _7$ reacts with $H _2 S$ under acidic conditions to give green product (A). (A) is :
→The standard e.m.f. of a call, involving one electron change is found to be $0.591\,V $ at $25\,^o C$. The equilibrium constant of the reaction is
→($F = 96,500\;C\;mo{l^{ - 1}}; \,\, R = 8.314\;J{K^{ - 1}}mo{l^{ - 1}})$