MCQ
Given standard electrode potentials

$F{e^{ + 2 }} + 2{e^ - }\, \to \,Fe\,;\,\,\,\,{E^o} = - 0.440\,V$

$F{e^{ + 3 }} + 3{e^ - }\, \to \,Fe\,;\,\,\,\,{E^o} = - 0.036\,V$The standard electrode potential $({E^o})$ for$F{e^{ + 3 }} + {e^ - } \to \,F{e^{ + 2 }}$ is  .............. $\mathrm{V}$

  • A
    $-0.476$
  • B
    $-0.404$
  • C
    $+ 0.404$
  • $+ 0.771$

Answer

Correct option: D.
$+ 0.771$
d
(d)$\Delta {G^o} = - n{E^o}\,F$

$F{e^{2 + }} + 2{e^ - } \to Fe$   …..$(i)$

$\Delta {G^o} = - 2 \times F \times ( - 0.440\,V) = 0.880\,F$

$F{e^{3 + }} + 3{e^ - } \to Fe$   …..$(ii)$

$\Delta {G^o} = - 3 \times F \times ( - 0.036) = 0.108\,F$

On subtracting equation $(i) $ from $(ii)$

$F{e^{3 + }} + {e^ - } \to F{e^{2 + }}$

$\Delta {G^o} = 0.108\,F - 0.880\,F = - 0.772\,F$

${E^o}$ for the reaction $ = - \frac{{\Delta {G^o}}}{{nF}}$ $ = - \frac{{( - \,0.772\,F)}}{{1 \times F}} = + \,0.772\,V$.

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