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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
Given that the dissociation constant for ${H_2}O$ is ${K_w} = 1 \times {10^{ - 14}}\,mol{e^2}/litr{e^2}$. What is the $pH$ of a $0.001$ molar $KOH$ solution
  • A
    ${10^{ - 11}}$
  • B
    ${10^{ - 3}}$
  • C
    $3$
  • ✓
    $11$
✓

Answer

Correct option: D.
$11$
(d) $pH = 14 - pOH$$ = 14 - 3$$ = 11$

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$\begin{array}{*{20}{c}}
  {\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - C - C{H_2} - \mathop C\limits^ \oplus  {H_2}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
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\end{array} \to \begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
  {\,\,\,\,\,\,|} \\ 
  {C{H_3} - \mathop C\limits^ \oplus   - CH - C{H_3}} \\ 
  {\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$   

How many ${H^ \ominus }$ shifts are involved in above rearrangement :

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