MCQ
Given the two concentration of $HCN (K_a = 10^{-9})$ are $0.1\,M$ and $0.001\,M$ respectively. What will be the ratio of degree of dissociation ?
- A$1$
- ✓$0.1$
- C$0.003$
- D$0.01$
✓
Answer
Correct option: B.
$0.1$
b
$\alpha=\sqrt{\frac{\mathrm{Ka}}{\mathrm{C}}}$
$\alpha=\sqrt{\frac{\mathrm{Ka}}{\mathrm{C}}}$
$\frac{\alpha_{1}}{\alpha_{2}}=\sqrt{\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}}$
$\frac{\alpha_{1}}{\alpha_{2}}=\sqrt{\frac{10^{-3}}{10}}=\sqrt{10^{-2}}=10^{-1}=\frac{1}{10}=0.1$
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