MCQ
Consider the reaction $N _{2} O _{4}( g ) \rightleftharpoons 2 NO _{2}( g )$

The temperature at which $K _{ C }=20.4$ and $K _{ P }=600.1,$ is ....... $K$. (Round off to the Nearest Integer).

[Assume all gases are ideal and $R =0.0831\, L\,bar \, K ^{-1} mol ^{-1}]$

  • A
    $124$
  • B
    $854$
  • C
    $354$
  • $345$

Answer

Correct option: D.
$345$
d
$N _{2} O _{4}( g ) \rightleftharpoons 2 NO _{2}( g ) ; \Delta n _{ g }=2-1=1$

$Now , K _{ p }= K _{ c } \cdot( RT )^{\Delta ng }$

or, $600.1=20.4 \times(0.0831\, \times T )^{1}$

$\therefore T =353.99\, K =354\, K$

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