Question
Gives the x-t plot of a particle executing one-dimensional simple harmonic motion. (You will learn about this motion in more detail in Chapter 14). Give the signs of position, velocity and acceleration variables of the particle at t = 0.3 s, 1.2 s, – 1.2 s.

Answer

For simple harmonic motion (SHM) of a particle, acceleration (a) is given by the relation:
$\text{a}=-\omega^2\text{x}$
Where $\omega$ = angular frequency
t = 0.3s
In this time interval, x is negative. Now the slope of the x-t plot is negative. Therefore, both position and velocity are negative. Acceleration of the particle using (i) will be positive.
t = 1.2s
In this time interval, x is positive. Now the slope of the x-t plot is positive. Therefore, both position and velocity are positive. Acceleration of the particle using (i) will be negative.
t = – 1.2s
In this time interval, x is negative. Now the slope of the x-t plot is positive. Therefore, position is negative and velocity is positive. Acceleration of the particle using (i) will be positive.

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