- A$ >C = O $
- B$ - C \equiv N$
- C$ >C = S $
- ✓All of the above

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$2H_2 + 2NO \to N_2 + 2H_2O$
the following mechanism has been proposed
$(i)$ $2NO \rightleftharpoons N_2O_2\,$ (fast)
$(ii)$ $N_2O_2 + H_2 \xrightarrow{{{k_2}}} N_2O + H_2O\,$ (slow)
$(iii)$ $N_2O + H_2 \to N_2 + H_2O\,$ (fast)
then what will be the rate law of this reaction ?
$k = A{e^{ - {E_a}/RT}}$
The activation energy $E_a$ of the reaction can be calculated by plotting
$\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
HOC{{H}_{2}}C{{H}_{2}}CHC{{H}_{2}}C{{H}_{2}}COH \\
\end{matrix}$ $\xrightarrow[tetrahydro\,\,futan ]{(x)\,\,C{{H}_{3}}Li}$ $\xrightarrow[{{H}_{2}}]{N{{H}_{4}}Cl}$ $\underset{Compound\,\,\,A\,\,63\,\%}{\mathop{\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\, \\
\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
HOC{{H}_{2}}C{{H}_{2}}CHC{{H}_{2}}C{{H}_{2}}-C-C{{H}_{3}} \\
\end{matrix}}}\,$ $\underset{37\,\%}{\mathop{+\,\,Compound\,\,(B)}}\,$
Value of $(x)$ in above reaction is