a The strength of $H$ - bond decreases in the following order $H \ldots . F \,>\, H \ldots . O\, >\, H....N$. It can be explained as below. The size of electronegative atoms should be small. The smaller the size of electronegative atoms, the greater is the attraction for the bonded electron pair. This causes greater polarity in the $H$ and the electronegative atom, resulting in stronger $H$ - bonding. The size of $F , O , N$ in the following order.
$F \,<\, O \,<\, N$
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આપેલ સ્પીસીઝોની કુલ સંખ્યા કે જે તેની સૌથી બાહ્ય કોશમાં મધ્યસ્થ પરમાણુ આસપાસ આઠ ઈલેક્ટ્રોનો ધરાવતા નથી તે... $NH _3, AlCl _3, BeCl _2, CCl _4, PCl _5:$