MCQ
$H_2O_2$ in basic medium reduces $I_2$ to form
- A$I^-$
- B$IO_3^-$
- ✓$I_3^-$
- D$IO_4^-$
✓
Answer
Correct option: C.
$I_3^-$
c
Due to larger size of iodine atom it can accommodate upto seven small fluorine atoms around, it while due to smaller sizes of chlorine and bromine atoms do not accommodate seven fluorine atoms, i.e., steric factor dominate in case of chlorine and bromine.
Due to larger size of iodine atom it can accommodate upto seven small fluorine atoms around, it while due to smaller sizes of chlorine and bromine atoms do not accommodate seven fluorine atoms, i.e., steric factor dominate in case of chlorine and bromine.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which has the minimum freezing point
In the form of dichromate$, \text{Cr (VI)}$ is a strong oxidising agent in acidic medium but $\text{Mo (VI)}$ in $\ce{MoO_3}$ and $\text{W(VI)}$ in $\ce{WO_3}$ are not because $.......$
$a. \text{Cr (VI)}$ is more stable than $\text{Mo (VI)}$ and $\text{W(VI)}$
$b. \text{Mo (VI)}$ and $\text{W(VI)}$ are more stable than $\text{Cr (VI)}.$
$c.$ Higher oxidation states of heavier members of group$-6$ of transition series are more stable.
$d.$ Lower oxidation states of heavier members of group$-6$ of transition series are more stable.
→$a. \text{Cr (VI)}$ is more stable than $\text{Mo (VI)}$ and $\text{W(VI)}$
$b. \text{Mo (VI)}$ and $\text{W(VI)}$ are more stable than $\text{Cr (VI)}.$
$c.$ Higher oxidation states of heavier members of group$-6$ of transition series are more stable.
$d.$ Lower oxidation states of heavier members of group$-6$ of transition series are more stable.
major product $(A)$ is
→Which of the following is non reducing sugar
Identify the wrong statement from the following
The Henry's law constant for the solubility of $N_2$ gas in water at $298\,K$ is $1.0 \times 10^5\, atm$. The mole fraction of $N_2$ in air is $0.8$. The number of moles of $N_2$ from air dissolved in $10\,moles$ of water at $298\,K$ and $5\,atm$ pressure will be
→Sulphur is used in:
In the following reaction sequence
→$CH_3CH_2OH$ $\xrightarrow{{P + {I_2}}}A\xrightarrow[{{\text{dry ether}}}]{{Mg}}B\xrightarrow{{HCHO}}C\xrightarrow{{{H_2}O}}D$ the compound $D$ is
Which of the following sets of reagents, used in the order shown, would successfully accomplish the conversion shown ?
Correct statement for $3d-$ series is
→