- AA tribasic acid
- ✓A dibasic acid
- CNeutral
- DA monobasic acid

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$[I]$ Only $A, B$ and $C$ react with $1\,M\,HCl$ to give $H_2\,(g)$
$[II]$ When $C$ is added to solutions of the other metal ions, metallic $B$ and $D$ are formed.
$[III]$ Metal $C$ does not reduce $A^{n+}$
$B + {H_2}O \to C + HCl$
Compound $(A),\,(B)$ and $(C)$ will be respectively
$\xrightarrow{{P + {I_2}}}\,\xrightarrow{{AgN{O_2}}}\,\xrightarrow{{HN{O_2}}}\,\,\xrightarrow{{NaOH}}$
$[A]$ $HClO_4$ is more acidic than $\mathrm{HClO}$ because of the resonance stabilization of its anion
$[B]$ $HClO_4$ is formed in the reaction between $Cl_2$ and $H_2 O$
$[C]$ The central atom in both $HClO_4$ and $HClO$ is $s p^3$ hybridized
$[D]$ The conjugate base of $HClO_4$ is weaker base than $H_2 O$
