MCQ
${H_3}P{O_3}$ is
  • A
    A tribasic acid
  • A dibasic acid
  • C
    Neutral
  • D
    A monobasic acid

Answer

Correct option: B.
A dibasic acid
b
(b) ${H_3}P{O_3}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

An electrolyte
Based on the following information arrange four metals $A, B, C$ and $D$ in order of decreasing ability to act as reducing agents :- 

$[I]$ Only $A, B$ and $C$ react with $1\,M\,HCl$ to give $H_2\,(g)$

$[II]$ When $C$ is added to solutions of the other metal ions, metallic $B$ and $D$ are formed.

$[III]$ Metal $C$ does not reduce $A^{n+}$

$A + {H_2}O \to B + HCl$

$B + {H_2}O \to C + HCl$

Compound $(A),\,(B)$ and $(C)$ will be respectively

Out of the following which gives blue colour on reaction with

$\xrightarrow{{P + {I_2}}}\,\xrightarrow{{AgN{O_2}}}\,\xrightarrow{{HN{O_2}}}\,\,\xrightarrow{{NaOH}}$

The correct statement(s) about the oxoacids, $HClO_4$ and $HClO$, is(are)

$[A]$ $HClO_4$ is more acidic than $\mathrm{HClO}$ because of the resonance stabilization of its anion

$[B]$ $HClO_4$ is formed in the reaction between $Cl_2$ and $H_2 O$

$[C]$ The central atom in both $HClO_4$ and $HClO$ is $s p^3$ hybridized

$[D]$ The conjugate base of $HClO_4$ is weaker base than $H_2 O$

Three moles of $\mathrm{AgCl}$ get precipitated when one mole of an octahedral co-ordination compound with empirical formula $\mathrm{CrCl}_{3} \cdot 3 \mathrm{NH}_{3} \cdot 3 \mathrm{H}_{2} \mathrm{O}$ reacts with excess of silver nitrate. The number of chloride ions satisfying the secondary valency of the metal ion is $......$
$Pb$ is a very important element of carbon family. It forms a number of compounds which are very useful in industries. The process of removal of base metals $(\text{Cu, Sn, Bi, As})$ from lead is called:
$\begin{array}{*{20}{c}}
  {CH = O} \\ 
  {\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,{{(CH - OH)}_4}\,\,\,} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {\,\,\,\,\,\,C{H_2} - OH} 
\end{array}$ $\xrightarrow{{B{r_2}/{H_2}O}}$ $P; P$ is
Glycerol on treatment with oxalic acid at $110\,^o C$ forms 
For the below given cyclic hemiacetal $(X)$, the correct pyranose structure is.