$H_4P_2O_5, H_4P_2O_6,$$H_4P_2O_7$ માં $P$ નો ઓક્સિડેશન આંક અનુક્રમે શું હશે ?

Question

AIPMT 2010, Easy

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Solution

d
The oxidation state can be calculated as

$\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{5}:+4+2 x+5(-2)=0$$\Rightarrow 2 x-6=0$$\Rightarrow x=+3$

$\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{6}:+4+2 x+6(-2)=0$$\Rightarrow 2 x-8=0$$\Rightarrow x =+4$

$\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{7}:+4+2 x+7(-2)=0$$\Rightarrow 2 x-10=0$$\Rightarrow 2 x=10$$\Rightarrow x=+5$

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