$3C{H_3} - CH = C{H_2} + B{H_3}\,\xrightarrow{{{\text{(Hydroboration)}}}}$ ${(C{H_3}C{H_2}C{H_2})_3}B$ $\xrightarrow[{{\text{(Oxidation)}}}]{{{H_2}{O_2}/O{H^ - }}}$ ${\text{3 C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{C}}{{\text{H}}_2}{\text{OH}}$