(a) $C{H_3}\, - \,\,\mathop C\limits_{\mathop |\limits_{C{H_3}} } \, = \,\,C{H_2}\,\xrightarrow{{HBr}}\,\,C{H_3}\, - \,\,\mathop {\mathop C\limits_{\mathop |\limits_{C{H_3}} } }\limits^{\mathop |\limits^{Br} } \,\, - \,\,C{H_3}$
(b) $C{H_3}\, - \,\,CH\,\, = \,\,C{H_2}\,\mathop {\xrightarrow{{HBr}}}\limits_{Peroxide} \,\,C{H_3}\,C{H_2}\,C{H_2}\,Br$
(c) $C{H_4}\, + \,\,C{l_2}\,\xrightarrow{{hv}}\,\,C{H_3}Cl\,\, + \,\,HCl$
$\mathop C\limits_6 {H_3} - \mathop C\limits_5 H = \mathop C\limits_4 H - \mathop C\limits_3 {H_2} - \mathop C\limits_2 \equiv \mathop C\limits_1 H$
કાર્બન્સ $1, 3$ અને $5$ ના સંકરણની સ્થિતિ નીચેના ક્રમમાં છે, તો સાચો ક્રમ શોધો.
$A \xrightarrow[ { Cu\; tube }]{\text { Redhot }}\mathrm{B} \xrightarrow[ Anhydrous AlCl_3]{\mathrm{CH}_{3} \mathrm{Cl}(1 \mathrm{eq}} \mathrm{C}$
($A$ એ સૌથી ઓછું પરમાણ્વીય વજન ધરાવતું આલ્કાઇન છે)