MCQ
Highest $pH =14$ is given by
- A$0.1\,M\,{H_2}S{O_4}$
- B$0.1\,M\,NaOH$
- ✓$1\,N\,NaOH$
- D$1\,N\,HCl$
$[O{H^ - }] = 1;\,\,pOH = 0$; $pH + pOH = 14$
$pH = 14 - 0 = 14$
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$(i)\, {CCl_3}^-$ $(ii)\,CCl_2$ $(iii)\, (SiH_3)_2O$ $(iv)\, N(SiH_3)_3$
$x\,\,\,\,\,\,\,\,\,\,y\,\,\,\,\,\,\,\,\,\,z$
If dilute $HCl$ is added to an aqueous solution of ${H_2}S$ without any change in temperature
