MCQ
$HN{O_2}$ acts as
- AOxidising agent
- BReducing agent
- ✓Both (a) and (b)
- DIts solution is stable
✓
Answer
Correct option: C.
Both (a) and (b)
c
(c) Nitrous acid behaves as reducing as well as an oxidising agent.
(c) Nitrous acid behaves as reducing as well as an oxidising agent.
It reduces potassium permanganate, potassium dichromate, ${H_2}{O_2}$ and other strong oxidising agents. It oxidises strong reducing agents such as hydroiodic acid, sulphurous acid etc.
It oxidises $F{e^{ + 2}}$ into $F{e^{ + 3}}$ in acidic medium;
$F{e^{ + 2}} + HN{O_2} + {H^ + }\, \to \,F{e^{ + 3}} + NO + {H_2}O$
It reduces acidified $KMn{O_4}$.
$2KMn{O_4} + 3{H_2}S{O_4} + 5HN{O_2}\, \to $
${K_2}S{O_4} + 2MnS{O_4} + 3{H_2}O + 5HN{O_3}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
(image) $\xrightarrow{{NO_2^ \oplus }}$ Product is
→Major product obtained in the reaction is
Give reactivity order towards $HCN$
→$(I)$ $ Ph -COCH_3$
$(II)$ $CH_3 -CO -CH_3$
$(III)$ $CH_3 -CHO$
$(IV)$ $Ph -COCH_2 -CH_3$
Correct statement for $3d-$ series is
→Given below are two statements : one is labelled as Assertion $A$ and the other is labelled as Reason $R$
→Assertion $A$ : Aniline on nitration yields ortho, meta and para nitro derivatives of aniline.
Reason $R$: Nitrating mixture is a strong acidic mixture.
In the light of the above statements, choose the correct answer from the options given below
In collision theory of chemical reaction, $Z_{\text {AB }}$ represents
→Correct option($s$) for the following sequence of reactions is(are)
→$(A)$ $Q = KNO _2, W = LiAlH _4$
$(B)$ $R =$ benzenamine, $V = KCN$
$(C)$ $Q = AgNO _2, R =$ phenylmethanamine
$(D)$ $W = LiAlH _4, V = AgCN$
Toluene is oxidised to benzoic acid by
Kohlrausch's law states that at
$'A'$ and $'B'$ in the following reactions are ${image}$
→