MCQ
Hofmann degradation is given by:
  • Imide
  • B
    Acid chloride
  • C
    Acid anhydride
  • D
    None of these

Answer

Correct option: A.
Imide
a
Hofmann Bromamide degradation is given by imide and amide. Acetamide reacts with bromine and aqueous or alcoholic KOH to form methyl amine.

$\mathrm{CH}_{3} \mathrm{CONH}_{2}+\mathrm{Br}_{2}+4 \mathrm{KOH} \rightarrow \mathrm{CH}_{3} \mathrm{NH}_{2}+\mathrm{K}_{2} \mathrm{CO}_{3}+2 \mathrm{KBr}+2 \mathrm{H}_{2} \mathrm{O}$

This is Hoffmann bromamide degradation reaction. The amine formed contains one carbon

atom less than amide.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free