How are xenon fluorides XeF_2, XeF_4 and XeF_6 obtained? - Vidyadip

Question

How are xenon fluorides $XeF_2,\ XeF_4$ and $XeF_6$ obtained?

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Answer

All three binary fluorides of Xe are formed by direct union of elements under appropriate experimental conditions. $XeF_2$ can also be prepared by irradiating a mixture of Xenon and fluorine with sunlight or light from a pressure mercury are lamp.
$\text{Xe}(\text{g})+\text{F}_2(\text{g})\xrightarrow[]{\Delta \ \text{ at 675 K}}\text{XeF}(\text{g})$
$\text{Xe}(\text{g})+2\text{F}_2(\text{g})\xrightarrow[\text{sealed Ni vessel}]{\Delta \ \text{ at 75 K atm}}\text{XeF}_4(\text{g})$
$\text{Xe}(\text{g})+3\text{F}_2(\text{g})\xrightarrow[\text{sealed Ni vessel}]{\Delta \ \text{ at 475-975 K}}\text{XeF}_6(\text{g})$

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