Question
How are $XeO_3$ and $XeOF_4$ prepared?

Answer

Preparation of $XeO _3$ : Xenon trioxide $\left( XeO _3\right)$ is prepared by the hydrolysis of $XeF _4$ or $XeF _6$.
- By hydrolysis of $XeF _4$ :
$3 XeF _4+6 H _2 O \rightarrow 2 Xe + XeO _3+12 HF +1 \frac{1}{2} O _2$
- By hydrolysis of $XeF _6$ :
$XeF _6+3 H _2 O \rightarrow XeO _3+6 HF$
- Preparation of $XeOF _4$ :
Xenon oxytetrafluoride $\left( XeOF _4\right)$ is prepared by the partial hydrolysis of
$XeF _6$.
$XeF _6+ H _2 O \rightarrow XeOF _4+2 HF$

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