- ABy dehydrohalogenation
- BBy dehydrogenation
- ✓By dehydration with conc. ${H_2}S{O_4}$ at ${170\,^o}C$
- DBy reduction with hydrogen iodide
The reaction of ethene with steam to form ethanol can be reversed. This allows ethanol to be converted into ethene. This is called a dehydration reaction.
$\underset{Ethanol}{C _2 H _5 OH} \xrightarrow[160^{\circ}-170^{\circ} C]{Conc. H _2 SO _4} \underset{Ethene}{CH _2= CH _2}+ \underset{Water}{H _2 O}$
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For the given reaction, if the initial pressure is $450\,mm Hg$ and the pressure at time $t$ is $720\,mm\,Hg$ at a constant temperature $T$ and constant volume $V$. The fraction of $A ( g )$ decomposed under these conditions is $x \times 10^{-1}$. The value of $x$ is $......$.(nearest integer)
$C{H_3} - \mathop {\mathop {N\, - \,}\limits_{|\,\,\,\,\,\,} }\limits_{C{H_3}} \mathop {\mathop {C\,\,\, - }\limits_{|\,\,\,\,\,\,\,}^{|\,\,\,\,\,\,\,} }\limits_{{C_2}{H_5}}^{C{H_3}} C{H_2} - C{H_3}$
$O(g) + e^- = O^-(g)$ $\Delta {H_{eg}} = - 142\,kJ\,mo{l^{ - 1}}$
$O^-(g) + e^- = O^{2-}(g)$ $\Delta {H_{eg}} = +844\,kJ\,mo{l^{ - 1}}$
This is because

