MCQ
How is galvanometer converted into a voltmeter?
  • A
    By connecting a high resistance multiplier in parallel to the galvanometer.
  • B
    By connecting a low resistance multiplier in parallel to the galvanometer.
  • C
    By connecting a low resistance multiplier in series with the galvanometer.
  • By connecting a high resistance multiplier in series with the galvanometer.

Answer

Correct option: D.
By connecting a high resistance multiplier in series with the galvanometer.
A galvanometer can be converted into voltmeter of given range by connecting a high resistance called multiplier in series with the galvanometer, whose value is given as:
$\text{R}\Big(\frac{\text{V}}{\text{I}_\text{g}}\Big)-\text{G}$
Where $V$ is the voltage to be measured, $l_g$ is the current for full scale deflection of galvanometer and $G$ is the resistance of galvanometer.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A sine wave is travelling in a medium. A particular particle has zero displacement at a certain instant. The particle closest to it having zero displacement is at a distance:
For which gate output is high, if at least one input is low ?
Which of the following is based on mechanical effect of electric current?
An electric dipole is placed in a uniform electric field. The net electric force on the dipole.
A fish looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is $\frac {4}{3}$ and the fish is $12\,cm$ below the surface, the radius of this circle in $cm$ is
A glass slab of thickness 3 cm and refractive index 3/2 is placed on ink mark on a piece of paper. For a person looking at the mark at a distance 5.0 cm above it, the distance of the mark will appear to be
A particle of mass $1\ gm$ and charge $ - 0.1\,\mu C$ is projected from ground with a velocity $10\sqrt 2 $ at an $45^o$ with horizontal in the area having uniform electric field $1\ kV/cm$ in horizontal direction. Acceleration due to gravity is $10\ m/s^2$ in vertical downward direction. Select $INCORRECT$ statement
Faraday's laws of electrolysis are related to
The dielectric constant $k$ of an insulator cannot be
A particle is rotated in a vertical circle by connecting it to a string of length l and keeping the other end of the string fixed. The minimum speed of the particle when the string is horizontal for which the particle will complete the circle is: