MCQ
How many moles of electrons weigh one kilogram?
- A$\frac{1}{2.108} \times 10^{31}$
- B$6.023 \times 10^{23}$
- C$\frac{6.023}{9.108} \times 10^{54}$
- D$\frac{1}{9.108 \times 6.023} \times 10^8$
✓
Answer
D.$\frac{1}{9.108 \times 6.023} \times 10^8$
Explanation:
$9.108 \times 10^{-31} kg=1$ electron
$\therefore 1 kg=\frac{1}{9.108 \times 10^{-31}}$ electron
$=\frac{1}{9.108 \times 10^{-31}} \times \frac{1}{6.023 \times 10^{23}}$ mole electron
Explanation:
$9.108 \times 10^{-31} kg=1$ electron
$\therefore 1 kg=\frac{1}{9.108 \times 10^{-31}}$ electron
$=\frac{1}{9.108 \times 10^{-31}} \times \frac{1}{6.023 \times 10^{23}}$ mole electron
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