Question
How many multiples of $4$ lie between $10$ and $250$?

Answer

Let,
Multiple of 4 lie between $10$ and $250$
$12, 16, 20, ..... 248$
we know $a_n = a+ (n - 1)d$
Here,
First term $a= 12$
Difference $d = 16 - 12 = 4$
and Last $n^{th}$​​​​​​​ term $a_n = 248$
Then, $a_n = a + (n - 1)d$
$\Rightarrow 248 = 12 + (n - 1)4$
$\Rightarrow 248 = 12 + 4n - 4$
$\Rightarrow 4n = 248 - 12 + 4$
$\Rightarrow 4n = 240$
$\Rightarrow n = 60$
Hence, multiple of $4$ lies between $10$ and $250$ is $60.$

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