MCQ
How many products will be formed in this reaction ?


- A$10$
- ✓$2$
- C$3$
- D$4$

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(Round off to the Nearest integer) [Given : Atomic masses : $C =12.0 \,u , H : 1.0\, u,O : 16.0 \,u , Br =80.0 \,u ]$

$(i)\, 6C(s) + 3H_2(g) \to C_6H_6(l) ; \Delta H = +45.9\,kJ$
$(ii)\, H_2(g) +\frac {1}{2}O_2(g) \to H_2O(l) ; \Delta H = -285.9\,kJ$
$(iii) \,C(s) + O_2(g) \to CO_2(g) ; \Delta H = -393.5\,kJ$
.....$kJ$

$(I)$ electron affinity of $Y$ is high $(II)$ ionization energy of $X$ is low
$(III)$ lattice energy of $XY$ is high $(IV)$ lattice energy of $XY$ is low
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