MCQ
How many protons are present in $1.8\,g \,NH_4^+$ ............. $N_A$
  • A
    $1$
  • B
    $1.2$
  • $1.1$
  • D
    $11$

Answer

Correct option: C.
$1.1$
c
No. of protons in one $\mathrm{NH}_{4}^{+}$ ion $=7+4=11$

No. of $\mathrm{NH}_{4}^{+}$ ions in $1.8\, \mathrm{g}=\frac{1.8}{18} \times \mathrm{N}_{\mathrm{A}}=0.1\, \mathrm{N}_{\mathrm{A}}$

$\text { No. of protons in } 1.8\, \mathrm{g} \,\mathrm{NH}_{4}^{+} =11 \times 0.1\, \mathrm{N}_{\mathrm{A}}$

$=1.1 \,\mathrm{N}_{\mathrm{A}}$

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