Question
How many tiles whose length and breadth are $12 \ cm$ and $5 \ cm$ respectively will be needed to fit in a rectangular region whose length and breadth are $70 \ cm$ and $36 \ cm$ respectively.
✓
Answer
Length of the region $= 70 \ cm$
Breadth of the region $= 36 \ cm$
$\therefore$ Area of the rectangular region $= 70 \ cm$ $\times$ $36 \ cm$
$= 2520\ sq \ cm$
Area of a tile $= 12 \ cm$ $\times$ $5 \ cm = 60\ sq \ cm$
$\therefore$ Number if tiles needed to fit the region
$=\frac{\text { Area of the region }}{\text { Area of a tile }}$
$=\frac{2520}{60}$
$= 42$
Breadth of the region $= 36 \ cm$
$\therefore$ Area of the rectangular region $= 70 \ cm$ $\times$ $36 \ cm$
$= 2520\ sq \ cm$
Area of a tile $= 12 \ cm$ $\times$ $5 \ cm = 60\ sq \ cm$
$\therefore$ Number if tiles needed to fit the region
$=\frac{\text { Area of the region }}{\text { Area of a tile }}$
$=\frac{2520}{60}$
$= 42$
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