Question
How many two-digit numbers are divisible by $6?$
✓
Answer
The two-digit numbers divisible by $6$ start from
$12, 18, 24, ..., 96$
Here,
$a = 12$
$d = 6$
$a_n = a + (n - 1)d$
$\Rightarrow 96 = 12 + (n - 1)(6)$
$\Rightarrow 96 = 12 + 6n - 6$
$\Rightarrow 90 = 6n$
$\Rightarrow n = 15$
This, $15$ two-digit number are divisible by $6$.
$12, 18, 24, ..., 96$
Here,
$a = 12$
$d = 6$
$a_n = a + (n - 1)d$
$\Rightarrow 96 = 12 + (n - 1)(6)$
$\Rightarrow 96 = 12 + 6n - 6$
$\Rightarrow 90 = 6n$
$\Rightarrow n = 15$
This, $15$ two-digit number are divisible by $6$.
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