How the following conversion can be carried out?
2-Chloropropane to 1-propanol.
2-Chloropropane to 1-propanol.
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$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Cl}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3-\text{CH}-\text{CH}_3\xrightarrow[(\text{Dehydrohalogenation})]{\text{KOH(alc)}/\Delta}\text{CH}_3-\text{CH}=\text{CH}_2+\text{HCl}\\ \ \ \ \ \ \ \ \ \ \ \ \ 2-\text{Chloropropane}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Propene}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{HBr/Peroxide}\Bigg\downarrow\text{(Anti-Markovnikov addition)}\\ \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{OH}\xrightarrow[(\text{Nucleophilic subsititution})]{\text{Aq. KOH}/\Delta}\text{CH}_3-\text{CH}_2-\text{CH}_2+\text{Br}\\ \ \ \ \ \ \ 1-\text{Propanol}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1-\text{Bromopropane}$
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