Question
How will you affect the following two-step conversions? Diethyl ether into n-butane :
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Answer
$C _2 H _5- O - C _2 H _5+\underset{\text { conc (excess) }}{2 HI } \xrightarrow{\Delta} \underset{\text { Ethyl iodide }}{2 C _2 H _5 I + H _2 O }$
$\underset{\text { Ethyl iodide }}{ C _2 H _5 I + Na + C _2 H _5 I } \xrightarrow[\text { (Wurtz reaction) }]{\text { dry ether }} \underset{n \text {-Butane }}{ C _4 H _{10}}+ NaI$
$\underset{\text { Ethyl iodide }}{ C _2 H _5 I + Na + C _2 H _5 I } \xrightarrow[\text { (Wurtz reaction) }]{\text { dry ether }} \underset{n \text {-Butane }}{ C _4 H _{10}}+ NaI$
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