Question
How will you convert benzene into:
p-nitrobromobenzene.

Answer

Benzene can be converted into p-nitrobromobenzene as:

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

5.975g of the higher oxide of metal gave 5.575g of lower oxide on heating. The quantity of the lower oxide gave 5.175g of metal on reduction. Prove that these results are in accordance with the law of multiple proportions.
One mole of $\text{N}_2\text{H}_4$ loses 10 moles electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation number of N in Y? There is no change in oxidation state of H.
Fluorine reacts with ice and results in the change:
$H_2O(s) + F_2(g) → HF(g) + HOF(g)$
Justify that this reaction is a redox reaction.
What do you understand by,
  1. Inert pair effect.
  2. Allotropy.
  3. Catenation.
Write structural formulae for all the isomeric amines with molecular formula $\mathrm{C}_4 \mathrm{H}_{11} \mathrm{~N}$.
Following data is given for the reaction: $\text{CaCO}_3\text{(s)}\xrightarrow{ \ \ \ \ \ \ \ \ \ \ \ }\text{CaO(s)}+\text{CO}_2\text{(g)}$
$\Delta_\text{f}\text{H}^\ominus[\text{CaO}\text{(s)}]=-635.1\text{KJ mol}^{-1}$
$\Delta_\text{f}\text{H}^\ominus[\text{CO}_2\text{(g)}]=-393.5\text{KJ mol}^{-1}$
$\Delta_\text{f}\text{H}^\ominus[\text{CaCO}_3\text{(s)}]=-1206.9\text{KJ mol}^{-1}$
Predict the effect of temperature on the equilibrium constant of the above reaction.
How are $0.50 \mathrm{~mol} \mathrm{Na}_2 \mathrm{CO}_3$ and $0.50 \mathrm{M} \mathrm{Na}_2 \mathrm{CO}_3$ different?
How does $\mathrm{H}_2 \mathrm{O}_2$ behave as a bleaching agent?
The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction $2 A+4 B \rightarrow 3 C+4 D$  , when 5 moles of A react with 6 moles of $B$, then
i. Which is the limiting reagent?
ii. Calculate the amount of C formed?
Write the bond angles in $\mathrm{CH}_4, \mathrm{NH}_3$ and $\mathrm{H}_2 \mathrm{O}$ molecules and give reason.