How would you prepare a saturated solution of sodium chloride in water at $25^\circ C?$ What will happen if this solution is cooled to $10^\circ C?$
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Take some water in a beaker and heat it slowly with the help of burner. Now, start adding sodium chloride salt to the hot water with a spoon and stir it with a glass rod continuously so that sodium chloride goes on dissolving in water. Take the temperature of water up to $25^\circ C$ and then keeping this temperature constant, go on adding sodium chloride till no more sodium chloride dissolves in it and some undissolved crystals will be left at the bottom. The contents of the beaker are now filtered and the clear solution obtained is the saturated solution of sodium chloride at $25^\circ C.$ If the temperature is lowered from $25^\circ C$ to $10^\circ C,$ then some of the crystals of sodium chloride will separate out from the solution in the form of solute crystals.
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