How would you prepare a saturated solution of sodium chloride in water at $25^\circ C?$ What will happen if this solution is cooled to $10^\circ C?$
Download our app for free and get started
Take some water in a beaker and heat it slowly with the help of burner. Now, start adding sodium chloride salt to the hot water with a spoon and stir it with a glass rod continuously so that sodium chloride goes on dissolving in water. Take the temperature of water up to $25^\circ C$ and then keeping this temperature constant, go on adding sodium chloride till no more sodium chloride dissolves in it and some undissolved crystals will be left at the bottom. The contents of the beaker are now filtered and the clear solution obtained is the saturated solution of sodium chloride at $25^\circ C.$ If the temperature is lowered from $25^\circ C$ to $10^\circ C,$ then some of the crystals of sodium chloride will separate out from the solution in the form of solute crystals.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Iron powder and sulphur powder were mixed together and divided into two parts $A$ and $B.$ When part $A$ was heated strongly over a burner, then a substance $C$ was formed. The part $B$ was, however, not heated at all. When dilute hydrochloric acid was added to substance $C,$ then gas $D$ was evolved and when dilute hydrochloric acid was added to part $B$ then gas $E$ was evolved.