- ✓$sp$
- B$sp^2$
- C$sp^3$
- D$sp^3d$
Number of Hybridization $=$ Valence electron $+$ monovalent $+$ (negative charge $)-($ positive charge $) / 2$
If we look at the iodine atoms there are seven valence electrons in its outer shell and two monovalent atoms are also present. Further, during the combination of Iodine with the two other lodine atoms, the central atom gains a negative charge whose value will be taken as 1 .
If we place or substitute the values according to the formula, we get
$7+1+2 / 2$
$=10 / 2$
$=5$
Therefore the hybridisation number is equal to $5$. Now we can say that hybridisation is $sp ^3 d$.
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$(A)$ Albumin is a simple protein
$(B)$ The amino acid alanine contains an acidic side chain
$(C)$ Insulin is a hormone
$(D)$ Muscles contain the protein keratin
Point out the wrong statements in the above set of statements

Maleic anhydride can be prepared by :
$Cu^+ + e^-\to Cu$, $E^o = X_2$
Calculate $E^o$ for $Cu^{+2} + e^-\to Cu^+$