MCQ
Hydrogen ion concentration in $mol/L$ in a solution of $pH = 5.4$ will be
- A$3.98 \times {10^8}$
- B$3.88 \times {10^6}$
- C$3.68 \times {10^{ - 6}}$
- ✓$3.98 \times {10^{ - 6}}$
$5.4 = - \log \,[{H^ + }]$; $[{H^ + }] = 3.98 \times {10^{ - 6}}$.
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