MCQ
Hydrolysis of $PCl_5$ gives
- A$H_3PO_2$
- B$H_3PO_3$
- ✓$H_3PO_4$
- DNone of these

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$[Cr(NH_3)_6] [Cr(NO_2)_6]$ and $[Cr(NH_3)_4(NO_2)_2] \,[Cr(NH_3)_2(NO_2)_4]$

$[Figure]$ $\xrightarrow{{{H^ + }/H{g^{2 + }}}}A$
the product '$ A'$ is