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The d- and f-Block Elements — Chemistry STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 ScienceChemistryThe d- and f-Block Elements2 Marks
Question
(i) $Ce ^{+4}$ is a strong oxidant, why?
(ii) $Eu ^{2+}$ is a strong reducing agent, why?
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Answer

(i) Despite $Ce ^{+4}$ having excellent gas configuration, it is a strong oxidant because the value of standard electrode potential for $Ce ^{+4} / Ce ^{+3}$ is high, hence it easily accepts electrons and transforms into $Ce ^{+3}$ (normal oxidation state). Hence it oxidizes water also.
(ii) $Eu ^{2+}$ is a strong reducing agent because it gets converted into +3 , the normal oxidation state of lanthanoids by giving up an electron.

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