MCQ
$(i)\,Al\,\xrightarrow{{{N_2}}}\,A$ $(ii)\,Al\,\xrightarrow{c}\,B$
Here $A$ and $B$ on hydrolysis respectively gives
- A$NH_3, \,C_2H_2$
- B$NO,\, CH_4$
- ✓$NH_3,\,CH_4$
- D$NO,\,C_2H_2$
✓
Answer
Correct option: C.
$NH_3,\,CH_4$
c
$A = AlN \xrightarrow{{{H_2}O}} NH_3$
$A = AlN \xrightarrow{{{H_2}O}} NH_3$
$B = Al_ 4C_3 \xrightarrow{{{H_2}O}} CH_4$
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