Answer

Correct option: D.
Scandiam $(Z=21)$
(d) : Scandium compounds are colourless,
$Sc ^{3+}$ has zero $d$-electrons.
$Sc (21):[ Ar ] 3 d^1 4 s^2$
$Sc ^{3+}:[ Ar ] 3 d^0 4 s^{\circ}$

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