
- A$A = P, B = Q$
- B$A = Q, B = R$
- ✓$A = Q, B = P$
- D$A = R, B = P$


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( $p$ : pressure, $V$ : volume, $T$ : temperature, $H$ : enthalpy, $S$ : entropy)
$A.$ For 1 s orbital, the probability density is maximum at the nucleus.
$B.$ For $2 s$ orbital, the probability density first increases to maximum and then decreases sharply to zero.
$C.$ Boundary surface diagrams of the orbitals encloses a region of $100 \%$ probability of finding the electron.
$D.$ $p$ and d-orbitals have $1$ and $2$ angular nodes respectively.
$E.$ Probability density of p-orbital is zero at the nucleus.
$\left[\right.$ Given $: \mathrm{h}=6.63 \times 10^{-34} \,\mathrm{Js}$ and $\left.\mathrm{c}=3.0 \times 10^{8} \,\mathrm{~ms}^{-1}\right]$