- AGlycine
- BAlanine
- ✓Arginine
- DAspartic acid
${H_2}N\, - \mathop C\limits^{\mathop {||}\limits^{NH} } - \,NH\, - \,C{H_2}\, - \,C{H_2}\, - \,\,C{H_2} - \mathop C\limits_{\mathop |\limits_H }^{\mathop |\limits^{N{H_2}} } - \,\mathop C\limits^{\mathop {||}\limits^O } - \,OH$
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$A$. $\mathrm{Mn}_2 \mathrm{O}_7$ is an oil at room temperature
$B$. $\mathrm{V}_2 \mathrm{O}_4$ reacts with acid to give $\mathrm{VO}_2^{2+}$
$C$. $\mathrm{CrO}$ is a basic oxide
$D$. $\mathrm{V}_2 \mathrm{O}_5$ does not react with acid
Choose the correct answer from the options given below :
$\begin{array}{*{20}{c}}
{O\,\,\,\,} \\
{||\,\,\,\,} \\
{C{H_3} - CH - C - C{H_2} - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{C{F_3}COOOH}}[X]$ as main product
$[X]$ will be :
$\begin{matrix}
\begin{matrix}
\,\,\,\,\,C{{H}_{3}} \\
| \\
\end{matrix}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C-C{{H}_{2}}C{{H}_{2}}OH \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$ $\xrightarrow[{{H_2}O,heat}]{{{K_2}C{r_2}{O_7};{H_2}S{O_4}}}A$ $\xrightarrow{{SOC{l_2}}}B\xrightarrow[{(2{\kern 1pt} mole)}]{{{{(C{H_3})}_2}NH}}C$ $\xrightarrow[{2.{\kern 1pt} {H_2}O}]{{\begin{array}{*{20}{c}}
{1.{\kern 1pt} LiAl{H_4}} \\
{diethyl{\kern 1pt} {\kern 1pt} ether}
\end{array}}}D$
$A$, (molecular formula $\left.\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2}\right)$ with a straight chain structure gives a $C_{4}$ carboxylic acid. $A$ is :
$A \frac{{Li} {A} {H} {H}_{4}}{{H}_{3} {O}^{+}} \longrightarrow B \stackrel{\text { Oxidation }}{\longrightarrow} {C}_{4}-$ carboxylic acid
Location $1$ $-$ Location $2$