MCQ
Identify the correct order of the size of the following:
  • $Ca^{2+} < K^+ < Ar < Cl^- < S^{2-}$
  • B
    $Ar < Ca^{2+} < K^+ < Cl^- < S^{2-}$
  • C
    $Ca^{2+} < Ar < K^+ < Cl^- < S{2-}$
  • D
    $Ca^{2+} < K^+ < Ar < S^{2-} < Cl^-$

Answer

Correct option: A.
$Ca^{2+} < K^+ < Ar < Cl^- < S^{2-}$
a
A cation has always the lesser ionic size than a metal atom due to loss of electrons and an anion has always the greater size than metal atom due to gain of electrons. So, the correct order of size is as

$C a^{2+} < K^{+} < A r < C I^{-} < S^{2-}$

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