The bond order of a molecule is given by - Vidyadip

MCQ

The bond order of a molecule is given by

A
The difference between the number of electrons in bonding and antibonding orbitals
B
Total number of electrons in bonding and antibonding orbitals
C
Twice the difference between the number of electrons in bonding and antibonding electrons
✓
Half the difference between the number of electrons in bonding and antibonding electrons

✓

Answer

Correct option: D.

Half the difference between the number of electrons in bonding and antibonding electrons

d

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 4. Chemical bonding and molecular structure→4. Chemical bonding and molecular structure — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Which of the following can not show geometrical isomerism ?

Which of the following is/ are the primary precursor $(s)$ of the photochemical smog?

Correct energy value order is

Deviation from Markownikoff's rule occurs in presence of

All the hydrocarbons shown are very weak acids. One, however, is far more acidic than the others. Which one is the strongest acid ?

Which of the following compounds represents acrylonitrile

$\ce{H_2O}$ is a:

Which of the following molecule contains both ionic and covalent bond

Which of the following reactions are disproportionation reactions?

(A) $\mathrm{Cu}^{+} \rightarrow \mathrm{Cu}^{2+}+\mathrm{Cu}$

(B) $3 \mathrm{MnO}_4^{2-}+4 \mathrm{H}^{+} \rightarrow 2 \mathrm{MnO}_4^{-}+\mathrm{MnO}_2+2 \mathrm{H}_2 \mathrm{O}$

(C) $2 \mathrm{KMnO}_4 \rightarrow \mathrm{K}_2 \mathrm{MnO}_4+\mathrm{MnO}_2+\mathrm{O}_2$

(D) $2 \mathrm{MnO}_4^{-}+3 \mathrm{Mn}^{2+}+2 \mathrm{H}_2 \mathrm{O} \rightarrow 5 \mathrm{MnO}_2+4 \mathrm{H}^{+}$

Choose the correct answer from the options given below:

The successive ionisation energy values for an element $X$ are given below element $X$ belongs to group :-
$A. 1^{st}$ ionisation energy $= 410\, kJ\, mol^{-1}$
$B. 2^{nd}$ ionisation energy $= 820\, kJ\, mol^{-1}$
$C. 3^{rd}$ ionisation energy $= 1100\, kJ\, mol^{-1}$
$D. 4^{th}$ ionisation energy $= 1500\, kJ\, mol^{-1}$
$E. 5^{th}$ ionisation energy $= 3200\, kJ\, mol^{-1}$